inspection

`set.issuperset`

Returns True if every element of other is in s. Method form accepts any iterable; >= requires a set. Use > for strict (proper) superset.

Syntax

s.issuperset(other)  |  s >= other

Parameters

Parameter	Purpose
other	An iterable (method) or set (operator) whose elements must all be in s
returns	bool

>>> {1, 2, 3}.issuperset({1, 2})
True

s contains every element of the argument.

>>> {1, 2} >= {1, 2}
True
>>> {1, 2} > {1, 2}
False

>= allows equality; > is strict/proper superset.

>>> {1, 2, 3}.issuperset([1, 4])
False

4 is not in s, so it is not a superset.

>>> {1, 2}.issuperset([])
True

Every set is a superset of the empty set/iterable.

>= and > require a set on the right; use .issuperset() for arbitrary iterables. It is the mirror of issubset: a >= b is equivalent to b <= a.